| 1 | import java.io.*; |
| 2 | |
| 3 | public class StringInfo { |
| 4 | /** |
| 5 | * Return the number of 'a's plus the number of 'b's in s. |
| 6 | * Precondition: s != null. |
| 7 | */ |
| 8 | public static int numAsAndBs(String s) { |
| 9 | int count= 0; |
| 10 | for(int i= 0; i < s.length(); i++) { |
| 11 | if(s.charAt(i) == 'a' || s.charAt(i) == 'b') { |
| 12 | count++; |
| 13 | } |
| 14 | } |
| 15 | return count; |
| 16 | } |
| 17 | |
| 18 | |
| 19 | /** |
| 20 | * A run is a sequence of the same character. Return the letter |
| 21 | * that has the longest run in s. For example, in "aaabbbbccaa", |
| 22 | * 'b' would be the result, since it occurs 4 times in a row. |
| 23 | * Precondition: s != null && s.length() > 0. |
| 24 | */ |
| 25 | public static char longestRun(String s) { |
| 26 | char longest= s.charAt(0); |
| 27 | char tempLongest= s.charAt(0); |
| 28 | int count= 1; |
| 29 | int tempCount= 1; |
| 30 | |
| 31 | for(int i= 1; i < s.length(); i++) { |
| 32 | if(s.charAt(i) == tempLongest) { |
| 33 | tempCount++; |
| 34 | } else { |
| 35 | if(tempCount > count) { |
| 36 | count= tempCount; |
| 37 | longest= tempLongest; |
| 38 | } |
| 39 | tempCount= 1; |
| 40 | tempLongest= s.charAt(i); |
| 41 | } |
| 42 | } |
| 43 | if(tempCount > count) { |
| 44 | count= tempCount; |
| 45 | longest= tempLongest; |
| 46 | } |
| 47 | |
| 48 | return longest; |
| 49 | } |
| 50 | |
| 51 | |
| 52 | /** |
| 53 | * Return whether s contains every letter in t. For example, |
| 54 | * "abcd" contains all the letters in "bbdc", since every letter |
| 55 | * in the second String appears in the first. |
| 56 | * Precondition: s != null && t != null. |
| 57 | */ |
| 58 | public static boolean contains(String s, String t) { |
| 59 | boolean contains= true; |
| 60 | for(int i= 0; contains && i < t.length(); i++) { |
| 61 | contains= contains && (s.indexOf(t.charAt(i)) >= 0); |
| 62 | } |
| 63 | return contains; |
| 64 | } |
| 65 | |
| 66 | |
| 67 | /** |
| 68 | * Return whether s contains every letter in t, including duplicate |
| 69 | * letters. For example, "abcd" does not contain all the letters in |
| 70 | * "bbdc", since there is only 1 'b' in "abcd". |
| 71 | * Precondition: s != null && t != null. |
| 72 | */ |
| 73 | public static boolean containsAllOf(String s, String t) { |
| 74 | boolean containsAll= true; |
| 75 | for(int i= 0; containsAll && i < t.length(); i++) { |
| 76 | int loc= s.indexOf(t.charAt(i)); |
| 77 | if (loc >= 0) { |
| 78 | s= s.substring(0, loc) + s.substring(loc + 1); |
| 79 | } else { |
| 80 | containsAll= false; |
| 81 | } |
| 82 | } |
| 83 | return containsAll; |
| 84 | } |
| 85 | |
| 86 | |
| 87 | /** |
| 88 | * Read a series of Strings from file f, and return the longest String, |
| 89 | * or null if the file is empty. |
| 90 | * Precondition: f != null. |
| 91 | */ |
| 92 | public static String getLongest(String f) throws IOException { |
| 93 | BufferedReader br= new BufferedReader(new FileReader(f)); |
| 94 | String longest= null; |
| 95 | String line= br.readLine(); |
| 96 | while(line != null) { |
| 97 | if (longest == null || line.length() > longest.length()) { |
| 98 | longest= line; |
| 99 | } |
| 100 | line= br.readLine(); |
| 101 | } |
| 102 | return longest; |
| 103 | } |
| 104 | |
| 105 | |
| 106 | /** |
| 107 | * Read a series of Strings from file f until one is found that |
| 108 | * is longer than the sum of the lengths of the previous two, or |
| 109 | * null if no such Strings are found. |
| 110 | * Precondition: f != null. |
| 111 | */ |
| 112 | public static String getLongerThanPreviousTwo(String f) throws IOException { |
| 113 | BufferedReader br= new BufferedReader(new FileReader(f)); |
| 114 | |
| 115 | /* The result. null until a line meeting the criterion is found or the |
| 116 | * end of the file is reached. |
| 117 | */ |
| 118 | String result= null; |
| 119 | |
| 120 | String l1= br.readLine(); // the penultimate line. |
| 121 | String l2= br.readLine(); // the previous line. |
| 122 | |
| 123 | String next= br.readLine(); // The next candidate. |
| 124 | while(next != null && result == null) { |
| 125 | if (next.length() > l1.length() + l2.length()) { |
| 126 | result= next; |
| 127 | } |
| 128 | l1= l2; |
| 129 | l2= next; |
| 130 | next= br.readLine(); |
| 131 | } |
| 132 | return result; |
| 133 | } |
| 134 | |
| 135 | |
| 136 | /** |
| 137 | * Read a series of Strings from file f, and return (concatenated without |
| 138 | * newlines) all the Strings that are longer than the sum of the lengths |
| 139 | * of the two previous to them, or null if no such Strings are found. |
| 140 | * Precondition: f != null. |
| 141 | */ |
| 142 | public static String getAllLongerThanPreviousTwo(String f) throws IOException { |
| 143 | BufferedReader br= new BufferedReader(new FileReader(f)); |
| 144 | |
| 145 | /* The result. null until a line meeting the criterion is found or the |
| 146 | * end of the file is reached. |
| 147 | */ |
| 148 | String result= null; |
| 149 | |
| 150 | String l1= br.readLine(); // the penultimate line. |
| 151 | String l2= br.readLine(); // the previous line. |
| 152 | |
| 153 | String next= br.readLine(); // The next candidate. |
| 154 | while(next != null) { |
| 155 | if (next.length() > l1.length() + l2.length()) { |
| 156 | if (result == null) { |
| 157 | result= next; |
| 158 | } else { |
| 159 | result += next; |
| 160 | } |
| 161 | } |
| 162 | |
| 163 | l1= l2; |
| 164 | l2= next; |
| 165 | next= br.readLine(); |
| 166 | } |
| 167 | return result; |
| 168 | } |
| 169 | |
| 170 | |
| 171 | } |